(3x+7)(x^2+4x-5)=0

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Solution for (3x+7)(x^2+4x-5)=0 equation: 


Simplifying
(3x + 7)(x2 + 4x + -5) = 0

Reorder the terms:
(7 + 3x)(x2 + 4x + -5) = 0

Reorder the terms:
(7 + 3x)(-5 + 4x + x2) = 0

Multiply (7 + 3x) * (-5 + 4x + x2)
(7(-5 + 4x + x2) + 3x * (-5 + 4x + x2)) = 0
((-5 * 7 + 4x * 7 + x2 * 7) + 3x * (-5 + 4x + x2)) = 0
((-35 + 28x + 7x2) + 3x * (-5 + 4x + x2)) = 0
(-35 + 28x + 7x2 + (-5 * 3x + 4x * 3x + x2 * 3x)) = 0
(-35 + 28x + 7x2 + (-15x + 12x2 + 3x3)) = 0

Reorder the terms:
(-35 + 28x + -15x + 7x2 + 12x2 + 3x3) = 0

Combine like terms: 28x + -15x = 13x
(-35 + 13x + 7x2 + 12x2 + 3x3) = 0

Combine like terms: 7x2 + 12x2 = 19x2
(-35 + 13x + 19x2 + 3x3) = 0

Solving
-35 + 13x + 19x2 + 3x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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